Integrand size = 29, antiderivative size = 204 \[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=-\frac {(g x)^{1+m} \left (d^2-e^2 x^2\right )^{3/2}}{g (4+m)}+\frac {d^2 (5+2 m) (g x)^{1+m} \sqrt {d^2-e^2 x^2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\frac {e^2 x^2}{d^2}\right )}{g (1+m) (4+m) \sqrt {1-\frac {e^2 x^2}{d^2}}}-\frac {2 d e (g x)^{2+m} \sqrt {d^2-e^2 x^2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},\frac {e^2 x^2}{d^2}\right )}{g^2 (2+m) \sqrt {1-\frac {e^2 x^2}{d^2}}} \]
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Time = 0.14 (sec) , antiderivative size = 204, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {866, 1823, 822, 372, 371} \[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=-\frac {2 d e \sqrt {d^2-e^2 x^2} (g x)^{m+2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {m+2}{2},\frac {m+4}{2},\frac {e^2 x^2}{d^2}\right )}{g^2 (m+2) \sqrt {1-\frac {e^2 x^2}{d^2}}}+\frac {d^2 (2 m+5) \sqrt {d^2-e^2 x^2} (g x)^{m+1} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {m+1}{2},\frac {m+3}{2},\frac {e^2 x^2}{d^2}\right )}{g (m+1) (m+4) \sqrt {1-\frac {e^2 x^2}{d^2}}}-\frac {\left (d^2-e^2 x^2\right )^{3/2} (g x)^{m+1}}{g (m+4)} \]
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Rule 371
Rule 372
Rule 822
Rule 866
Rule 1823
Rubi steps \begin{align*} \text {integral}& = \int (g x)^m (d-e x)^2 \sqrt {d^2-e^2 x^2} \, dx \\ & = -\frac {(g x)^{1+m} \left (d^2-e^2 x^2\right )^{3/2}}{g (4+m)}-\frac {\int (g x)^m \left (-d^2 e^2 (5+2 m)+2 d e^3 (4+m) x\right ) \sqrt {d^2-e^2 x^2} \, dx}{e^2 (4+m)} \\ & = -\frac {(g x)^{1+m} \left (d^2-e^2 x^2\right )^{3/2}}{g (4+m)}-\frac {(2 d e) \int (g x)^{1+m} \sqrt {d^2-e^2 x^2} \, dx}{g}+\frac {\left (d^2 (5+2 m)\right ) \int (g x)^m \sqrt {d^2-e^2 x^2} \, dx}{4+m} \\ & = -\frac {(g x)^{1+m} \left (d^2-e^2 x^2\right )^{3/2}}{g (4+m)}-\frac {\left (2 d e \sqrt {d^2-e^2 x^2}\right ) \int (g x)^{1+m} \sqrt {1-\frac {e^2 x^2}{d^2}} \, dx}{g \sqrt {1-\frac {e^2 x^2}{d^2}}}+\frac {\left (d^2 (5+2 m) \sqrt {d^2-e^2 x^2}\right ) \int (g x)^m \sqrt {1-\frac {e^2 x^2}{d^2}} \, dx}{(4+m) \sqrt {1-\frac {e^2 x^2}{d^2}}} \\ & = -\frac {(g x)^{1+m} \left (d^2-e^2 x^2\right )^{3/2}}{g (4+m)}+\frac {d^2 (5+2 m) (g x)^{1+m} \sqrt {d^2-e^2 x^2} \, _2F_1\left (-\frac {1}{2},\frac {1+m}{2};\frac {3+m}{2};\frac {e^2 x^2}{d^2}\right )}{g (1+m) (4+m) \sqrt {1-\frac {e^2 x^2}{d^2}}}-\frac {2 d e (g x)^{2+m} \sqrt {d^2-e^2 x^2} \, _2F_1\left (-\frac {1}{2},\frac {2+m}{2};\frac {4+m}{2};\frac {e^2 x^2}{d^2}\right )}{g^2 (2+m) \sqrt {1-\frac {e^2 x^2}{d^2}}} \\ \end{align*}
Time = 0.64 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.85 \[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\frac {x (g x)^m \sqrt {d^2-e^2 x^2} \left (d^2 \left (6+5 m+m^2\right ) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\frac {e^2 x^2}{d^2}\right )-e (1+m) x \left (2 d (3+m) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},\frac {e^2 x^2}{d^2}\right )-e (2+m) x \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},\frac {e^2 x^2}{d^2}\right )\right )\right )}{(1+m) (2+m) (3+m) \sqrt {1-\frac {e^2 x^2}{d^2}}} \]
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\[\int \frac {\left (g x \right )^{m} \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}{\left (e x +d \right )^{2}}d x\]
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\[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\int { \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} \left (g x\right )^{m}}{{\left (e x + d\right )}^{2}} \,d x } \]
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Result contains complex when optimal does not.
Time = 38.53 (sec) , antiderivative size = 182, normalized size of antiderivative = 0.89 \[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\frac {d^{3} g^{m} x^{m + 1} \Gamma \left (\frac {m}{2} + \frac {1}{2}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {m}{2} + \frac {1}{2} \\ \frac {m}{2} + \frac {3}{2} \end {matrix}\middle | {\frac {e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{2 \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} - \frac {d^{2} e g^{m} x^{m + 2} \Gamma \left (\frac {m}{2} + 1\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {m}{2} + 1 \\ \frac {m}{2} + 2 \end {matrix}\middle | {\frac {e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{\Gamma \left (\frac {m}{2} + 2\right )} + \frac {d e^{2} g^{m} x^{m + 3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {m}{2} + \frac {3}{2} \\ \frac {m}{2} + \frac {5}{2} \end {matrix}\middle | {\frac {e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{2 \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} \]
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\[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\int { \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} \left (g x\right )^{m}}{{\left (e x + d\right )}^{2}} \,d x } \]
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Exception generated. \[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {(g x)^m \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\int \frac {{\left (d^2-e^2\,x^2\right )}^{5/2}\,{\left (g\,x\right )}^m}{{\left (d+e\,x\right )}^2} \,d x \]
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